Computing Quorum

[Guest Michael Vaughn]

Bylaws require a quorum of 25% of membership; in determining the existence of a quorum, do you round up or down.  If membership is 68, then quorum would be 17; if membership if 72, then quorum would be 18.  What about membership figures of 69, 70 and 71.  If 69, then quorum would be 17 1/4 (round down to 17?); if 71, then quorum would be 17 3/4 (round up to 18?), but what if membership is 72, then quorum would be 17 1/2 -- round down to 17 or up to 18?

[Dan Honemann]

You need at least 25% of your members present. If there are 69 members, 18 need to be present.

[Guest Dömötör]

You can think about a quorum requirement this way: At least 25% of membership needs to be in attendance.

 

For 69 members, 25% is 17.25.  So you need at least that many members. Unless you are part of a dismemberment club, you can't get exactly 17.25, 17 won't cut it since it's less than 17.25, so 18 is the smallest (whole) number that's fulfills the "at least 17.25 members" rule.

 

Another way to think about it, attendance needs to be "greater than or equal to" the quorum requirement.

[Dan Honemann]

You can think about a quorum requirement this way: At least 25% of membership needs to be in attendance.

 

For 69 members, 25% is 17.25.  So you need at least that many members. Unless you are part of a dismemberment club, you can't get exactly 17.25, 17 won't cut it since it's less than 17.25, so 18 is the smallest (whole) number that's fulfills the "at least 17.25 members" rule.

 

Another way to think about it, attendance needs to be "greater than or equal to" the quorum requirement.

So this is why RONR refers to kicking a member out as expulsion rather then dismemberment.

[Guest Guest]

Thanks to everyone who posted a response -- very helpful -- and, Dan, thanks for the chuckle on this early Saturday morning.